# How do you evaluate the function with the given values of #x:color(white)("dd") h(x)=23x-1 ;color(white)("d")x=1/3;color(white)("d") x=-1#?

##### 1 Answer

May 19, 2018

#### Explanation:

#"to evaluate substitute the given values for x into "h(x)#

#h(color(red)(1/3))=(23xxcolor(red)(1/3))-1=23/3-3/3=20/3#

#h(color(red)(-1))=(23xxcolor(red)(-1))-1=-23-1=-24#